Getting an accurate reading of the contents of a vessel with complex shaped ends etc. Plugging these values into the volume formula gives us We have L = 15, A = 3, B = 4, and h = 2, since we must convert inches to feet. The tank is filled with water to a depth of 24 inches. Suppose an elliptical tank is 15 feet long, and 4 feet wide, and 3 feet tall when laid on its side. This gives you the elliptical area formula (pi/4)AB, and the elliptical tank volume formula (pi/4)ABL. To find the maximum area or maximum volume in the tank, set h = A, that is, set the height of the liquid equal to the height of the tank. If the tank has a length of L, then the corresponding volume formula is simply: If the height of the tank is A, the width of the tank B, and the height of the elliptical segment h then the area of the segment is given by the equation:Īrea = (AB/4), I'm not sure this will help but it's the formula I used recently to acertain the volume in a horizontal eliptical tank. Without additional details, I think it's best to offer this simple general explanation for now rather than trying to guess where you're hung up. There are different ways to do this, depending on what type of info you have (or don't have) on your tank. For a non-linear application, you could create a look up table to translate pressure to volume for your application. If you want to convert your pressure value to a volumetric one, use the correct scalar multiplier for a linear tank. This will be the same for linear or non-linear (horizontal/elliptical) tanks. The output will be in pressure/level units. Your scaled_min/scaled_max values should be the min/max range noted on your level transmitter. Make sure your input_min/input_max tag values are correct for your input signal. The Anderson level transmitter is going to output 4-20mA, equivalent to some pressure range (0-xxx"H2O).ĭepending on what type PLC & I/O module you're working with, your 4-20mA input signal in the processor could be in the range of 3277-16384, 4000-20000, or something else.
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